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The corner points of the feasible region for the Linear Programming Problem are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5). Let the objective function is Z= 4x +6y then the minimum value of the objective function occurs at

(a) (0, 2) only

(b) (3, 0) only

(c) The mid-point on the line segment joining the points (0,2) and (3,0)

(d) Any point on the line segment joining the points (0,2) and (3,0)

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Correct option is (d) Any point on the line segment joining the points (0,2) and (3,0)

Corner Points   Value of Z

A (0, 2)      Z = 0 + 12 = 12

B (3, 0)      Z = 12 + 0 = 12

C (6, 0)     Z = 24 + 0 = 24

D (6,8)      Z = 24 + 48 = 72

E (0,5)      Z = 0 + 30 = 30

Minimum value of Z = 12

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